(a^2-3ab)-(b^2-3ab)=

Solution for (a^2-3ab)-(b^2-3ab)= equation:

Simplifying
(a2 + -3ab) + -1(b2 + -3ab) = 0

Reorder the terms:
(-3ab + a2) + -1(b2 + -3ab) = 0

Remove parenthesis around (-3ab + a2)
-3ab + a2 + -1(b2 + -3ab) = 0

Reorder the terms:
-3ab + a2 + -1(-3ab + b2) = 0
-3ab + a2 + (-3ab * -1 + b2 * -1) = 0
-3ab + a2 + (3ab + -1b2) = 0

Reorder the terms:
-3ab + 3ab + a2 + -1b2 = 0

Combine like terms: -3ab + 3ab = 0
0 + a2 + -1b2 = 0
a2 + -1b2 = 0

Solving
a2 + -1b2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b2' to each side of the equation.
a2 + -1b2 + b2 = 0 + b2

Combine like terms: -1b2 + b2 = 0
a2 + 0 = 0 + b2
a2 = 0 + b2
Remove the zero:
a2 = b2

Simplifying
a2 = b2

Take the square root of each side:
a = {-1b, b}